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18:44:12Q.IF COT(X+Y)=0,THEN THE VALUE OF SIN(X+2Y)?
its answer is 1/√2
1/rt2 is the answer. First cot 90 =0 therefore x+y=pi/2
open cos(x+y) = 0
put x=pi/2-y in sin(x+2y) and then same for y. u will get cosy=sinx
solve furthur by opening cos(x+y) identity substitute and u will get 1/rt2
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