If cot(x+y)=0, then write the value of sin(x+2y).Show the solution

Question

MADHAV DHRUV · Answer

HERE , cot(x+y)=0 SO, ON SOLVING WE GET ,TANxTANy=1. so, SINxSINy=COSxCOSy NOW , SIN(x+2y)=SINxCOS2y+COSxSIN2y =SINx(1-2SINySINy)+COSx2SINyCOSy =SINx-2SINySINySINx+2SINySINySINx =SINx

siddhartha jain · Answer

From the given equation, cot(x+y)=0 so, cos(x+y)/sin(x+y)=0 => cos(x+y)=0 => x+y= &prod;/2 so, y= &prod;/2- x Now sin(x+2y)= sin(x+&prod;-2x) = sin(&prod;-x) = sin x Hence, sinx is the answer..

satyam vats · Answer

cot(a+b)=0 then,cos(a+b) =0 and,a+b=npi+pi/2 a=npi+pi/2-b and,b=npi+pi/2-a sin(a+2b)=sin(npi+pi/2+b)=+cos or -cos sin(a+2b)=sin(2npi+pi/2-a)=sina

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If cot(x+y)=0, then write the value of sin(x+2y).Show the solution

If cot(x+y)=0, then write the value of sin(x+2y).Show the solution

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