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solve for x and y
x^2+2xsin(xy)+1 = 0
x^2+2xsin(xy)+1=0
sin(xy)=-(x+1/x)/2 (a number and its reciprocal always greater that or equal to 2)
therefore sin(xy)=-1
xy=-pie/2 or =3/2*pie.....
infinete solutions...
(-1, pie/2) , (1,-pie/2)......
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