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Int (sinx)^4/(cosx)6
this is (sinx/cosx)^4 / cosx ^2
= (tanx)^4 * (secx)^2
put tanx = t
diff. sec^2x dx = dt
we get (t)^4 dt ( sec^2x dx = dt and tanx = t)
= t^5/5
= tanx^5 / 5
int tan x4 .sec x2 dx
=int tan x4 (1+tan x2) dx
=int tan x4 dx +int tan x6 dx it is the formula
=(tan x3) /3 -tan x +(tan x5 )/5 -(tan x3 )/3 +tan x
=(tan x5) /5
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