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how to solve:- sin2A+sin2B-sinc= 4cosAcosBsinC

how to solve:-


   sin2A+sin2B-sinc= 4cosAcosBsinC

Grade:10

1 Answers

BAYANA SAGAR
48 Points
10 years ago

sin2a+sin2b-sinc

=2sin(a+b)cos(a-b)-sinc

=2sinc(cos(a-b)+cos(a+b)

=2cosacosb(2sinc)

=4cosacosbsinc

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