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A boy standing in the middle of a field, observes a flying bird in the north at an angle of elevation fo 30 degree. and after 2 min, he observes the same bird in the south at an angle of elevation o f60 degree. If the bird flies all along in a straight line at a height of 50root3 m, then its speed in km/h is
ans is 6km/hr {take tan 60=50root 3/x , tan 30 =50 root 3/y , then add x+y ,this x+y is the distance travelled by it , given time t=2min=2/60 hrs you will get x+y=200m=0.2 km velocity =d/t=0.2*60/2 km/hr}
ans is 6km/hr
{take tan 60=50root 3/x , tan 30 =50 root 3/y , then add x+y ,this x+y is the distance travelled by it , given time t=2min=2/60 hrs
you will get x+y=200m=0.2 km
velocity =d/t=0.2*60/2 km/hr}
tan30=50√3/x 1/√3=50√3/x 150=x √3=50√3/y y=50 total distance covered =x+y=200m .2km time=2/60hr speed=6km/hr
tan30=50√3/x
1/√3=50√3/x
150=x
√3=50√3/y
y=50
total distance covered =x+y=200m
.2km
time=2/60hr
speed=6km/hr
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