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cosx = 2cosy-1/2-cosy,then tanx/2.coty/2=?
Please refer the below solution :-Put x = 90, we get :-cos90 = (2cosy - 1)/(2- cosy) Or 0 = 2cosy - 1Or cosy = 1/2 => y = 60.Putting x= 90 and y=60 in the given equation,tan(45) x cot(30) = 1 x (√3) = √3
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