Trigonometry
find the maximum value of 9sinA-i2sin^2A.
1 Answer
umesh panjwani
| 9sinA-i2sin^2A=y |
deffrentiate and then equate dy/dA=0
9cosA-i4sinAcosA=0
9cosA=isinAcosA
if A not equal to 90 degrees
9=isinA
sinA=9/i implies no solution
therefore, only 1 solution in case A is equal to 90 degrees
so, max value is 9-i
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