sin30=
nagaraju kondeti , 12 Years ago
Grade
Trigonometry> trigonometry
2 Answers
Kurma Anudeep
Last Activity: 12 Years ago
sin30=sin45-sin15=1/2
Ramya Ananth
Last Activity: 12 Years ago
Draw an equilateral triangle ABC.
Draw a perpendicular from A to BC intersecting BC at D
AB = AC (sides of an equilateral trianlge are equal)
Angle ADB = Angle ADC = 90
AD = AD
ΔADB ≅ ΔADC (RHS postulate)
BD = DC = (1/2)BC = (1/2)AB (congruence of triangles and sides of an equilateral triangle are equal)
Angle ABD = AngleDAC = 60/2 = 30 (congruence of triangles)
sinBAD = BD/AB = 1/2
sin(30) = 1/2
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