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if sin(2a)=4sin2b,show that 5tan(a-b)=3tan(a+b)
sin2a/sin4b=4sin2a+sin2b/sin2a-sin2b=4+1/4-1[by componendo & dividendo]2sin(a+b)cos(a-b)/2cos(a+b)sin(a-b)=5/3tan(a+b)/tan(a-b)=5/35tan(a-b)=3tan(a+b)Thanks & RegardsSunil RaikwaraskIITians Faculty
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