Join now for JEE/NEET and also prepare for Boards Join now for JEE/NEET and also prepare for Boards. Register Now
Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
If A+B+C=0 find maximum value of sinA+sinB+sinC If A+B+C=0 find maximum value of sinA+sinB+sinC
Hello Sudarshan sinA + sinB +sinC=2sin[(A+B)/2].cos[(A-B)/2]+2sin(C/2).cos(C/2) A+B+C=0=>A+B=-C Therefore sinA + sinB +sinC=2sin(C/2).cos[(A+B)/2]-2Sin(C/2).cos[(A-B)/2] =2sin(C/2).{cos[(A+B)/2]-cos[(A-B)/2} =2sin(A/2).sin(B/2).sin(C/2)
Hello Sudarshan
sinA + sinB +sinC=2sin[(A+B)/2].cos[(A-B)/2]+2sin(C/2).cos(C/2)
A+B+C=0=>A+B=-C
Therefore
sinA + sinB +sinC=2sin(C/2).cos[(A+B)/2]-2Sin(C/2).cos[(A-B)/2]
=2sin(C/2).{cos[(A+B)/2]-cos[(A-B)/2}
=2sin(A/2).sin(B/2).sin(C/2)
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -