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sin cot-1 tan cos-1x.
(tan)^3x
given sincot-1tancos-1x
but we know that cos-1x=tan-1(1-x2)1/2/x
= sincot-1tantan-1(1-x2)1/2/x
=sincot-1(1-x2)1/2/x (since tantan-1x=x)
=sinsin-1x
=x
therefore sincot-1tancos-1x=x
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