sin cot-1 tan cos-1x.

(tan)^3x

given  sincot^-1tancos^-1x

but we know that cos^-1x=tan^-1(1-x²)^1/2/x

= sincot^-1tantan^-1(1-x2)1/2/x

=sincot^-1(1-x²)^1/2/x                   (since tantan^-1x=x)

=sinsin^-1x

=x

therefore  sincot^-1tancos^-1x=x

I HOPE YOU WILL FIND TIS SOLUTION HELPFUL......

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