Trigonometry

Prove that square root of 3xcosec20 + sec20=4

Tanmay Bhoite

14 Years agoGrade

1 Answer

Arun Kumar

12 Years ago

Hello Student,

$\sqrt3cosec20 + sec20 \\={\sqrt3 \over sin20}+{1 \over cos20} \\={\sqrt3cos20+sin20 \over {1 \over 2}sin40} \\=>{2cos50 \over {1 \over 2}sin40} \\=>4$

Thanks & Regards
Arun Kumar
Btech, IIT Delhi
Askiitians Faculty

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Prove that square root of 3xcosec20 + sec20=4

Tanmay Bhoite

1 Answer

Arun Kumar

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