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the number of values of x in [0,5π],satisfying 3cos2x-10cosx=7=0 are i)4 ii)8 iii)6 iv)10
Hey Shaoni Chakravarty
Firstly I think you were asking 3cos2x - 10cosx + 7 = 0
(cos2x = 2cos²x - 1)
3(2cos²x-1)-10cosx+7=0
6cos²x-3-10cosx+7=0
6cos²x-10cosx+4=0
6cosx(cosx-1)-4(cosx-1)=0
(6cosx-4)(cosx-1)=0
cosx = 2/3
x=59,2∏+59,4∏+59
cosx=1
Therefore the expression totally has 6 values option (iii)
Hope this helped you so please can you approve it thank you
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