Trigonometry
in paper 2 of jee 2012,a question was like this:Let f : (–1, 1) ® IR be such that 2
2
(cos 4 )
2 sec
q =
- q
f for 0, ,
4 4 2
p p p qÎ È
. Then the value(s) of
1
3
f is (are)
(A)
3
1
2
- (B)
3
1
2
+
(C)
2
1
3
- (D)
2
1
3
+;isnt this question wrong,v r getting 2 values of y for 1 x.so,not a function,but it is mentioned in question f:....?
plzzzzzzzz reply now........
