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question mark

- secA ×cosecA =?Show working

tejas desai , 12 Years ago
Grade
anser 1 Answers
Jitender Singh

Last Activity: 10 Years ago

Ans: -2
Sol:
tanA(1-cotA)+cotA(1-tanA)-secA.cosecA
tanA(1-\frac{1}{tanA})+\frac{1}{tanA}(1-tanA)-\frac{1}{cosA}.\frac{1}{sinA}
\frac{(tanA-1)^{2}}{tanA}-\frac{2}{2sinA.cosA}
\frac{(tan^{2}A+1-2tanA)}{tanA}-\frac{2}{sin2A}
\frac{(tan^{2}A+1)}{tanA}-2-\frac{2}{\frac{2tanA}{1+tan^{2}A}}
=-2
Thanks & Regards
Jitender Singh
IIT Delhi
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