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Grade 12th PassTrigonometry

tan 6. tan 42. tan 66. tan 78. is equal to??? Explain how pls.

Profile image of Aditi Bhatnagar
14 Years agoGrade 12th Pass
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3 Answers

Profile image of Ashwin Muralidharan IIT Madras
14 Years ago

Hi Aditi,

Hope it helps.

Regards,

Ashwin (IIT Madras).

Profile image of Arya
8 Years ago
Given : tan6°tan42°tan66°tan78° = ?
Here we'll use the formula :
tan3x=(tanx)tan(60+x)tan(60-x)
Solution :-
  [  ( tan6°tan66°tan54°)/ tan54°]*[(tan42°tan78°tan18°)/tan18°] =1
 
Therefore the answer is 1.
 
Hope this'll help you..!! 
Profile image of ankit singh
5 Years ago
 
tan3x=(tanx)tan(60+x)tan(60-x)
Solution :-
  [  ( tan6°tan66°tan54°)/ tan54°]*[(tan42°tan78°tan18°)/tan18°] =1
 

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