+91-87964 74404
FlagBACK
Question icon
Grade 12th PassTrigonometry

If A =130 degrees and x= sin A + cos A THEN

(A) X>0 (B) X<0 (C) X=0 (D) X<=0

eXPLAIN PLS...ANS GIVEN IS (A)...

Profile image of Aditi Bhatnagar
14 Years agoGrade 12th Pass
Answers icon

2 Answers

Profile image of omi more
14 Years ago

x= sin(130) +cos(130)= sin 70* + (-cos 70*)    =>x>0 (since sin 70* would be greater than cos 70*)

Profile image of Venkat
7 Years ago
X= Sin130 + Cos130 =Sin(180-50) + Cos(180-50)
                                     =Sin50 - Cos50
                                     =Sin50 - Cos(90-40)
                                     =Sin50 - Sin40
                                     =Sin(45+5) - Sin(45-5)
                                     =2Cos45.Sin5 
                    Since, the value of 2cos45.sin5 is positive 
                         the value of X is also positive. 

Other Related Questions on trigonometry

question mark
In ABC, if cot A+cot B+cot C = cosecA cosecB cosecC, then prove that ABC is right angle triangle.
trigonometry
1 Answer Available

Last Activity: 3 Years ago

question mark
  • Find the general solution of equation tan3∂=cot2∂
For all angles between -720 and +720
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
To prove : Cosec(45 degree - A)Cosec(45 degree + A) = 2SecA
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
Derive a formula for the area of the triangle, given b, A, B, and C. That is, derive the formula: (b^2sinAsinC)/(2sinB)
trigonometry
1 Answer Available

Last Activity: 4 Years ago

question mark
WHAT IS THE LIMIT WHEN X TOWARDS TO 0 OF sin6x/5x ? lim𝑥→0 𝑠𝑖𝑛6𝑥/5𝑥 
trigonometry
1 Answer Available

Last Activity: 4 Years ago