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If x =(2 sin Θ)/(1+ cos????Θ + sinΘ), then (1 - cos Θ + sinΘ)/(1 + sinΘ ) is equal to
(a) 1+x (b) 1-x (c) x (d) 1/x
Pls explain.
given x = (2sinθ)/( 1+sinθ+cosθ)
multiplying the numerator and the denominator by (1+sinθ-cosθ)
x = (2sinθ)(1+sinθ-cosθ)/((1+sinθ)2-(cosθ)2)
on simplifying you will get same the desired as (1-cosθ+sinθ)/(1+sinθ) which is x.
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