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in the following problem, In a triangle ABC,if r1 is the exradius of the excircle opposite to A,r2 is the exradius of the excircle opposite to B and r3is the exradius of the excircle opposite to C.... prove that ( ar 1 +br 2 +cr 3 )/abc=(1/r)-(1/2R) where r is the inradius and R is the circum radius. i tried using these formulae: r1=(area of triangle)/(s-a) r1=stanA/2 but i cudnt solve it.how should i start?











in the following problem,


In a triangle ABC,if  r1 is the exradius of the excircle opposite to A,r2 is the exradius of the excircle opposite to B and r3is the exradius of the excircle opposite to C....


prove that (ar1+br2+cr3)/abc=(1/r)-(1/2R)


where r is the inradius and R is the circum radius.


i tried using these formulae:


r1=(area of triangle)/(s-a)


r1=stanA/2


but i cudnt solve it.how should i start?


Grade:12

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