Q1)If in a triangle, a= 6, b= 3 and cos(A-B)=4/5, then find its area?
Q2)Let the angles of a A,B,C of a triangle ABC be in A.P.and let b:c=under root(3):under root(2).Find the angle A?

Question

Q1)If in a triangle, a= 6, b= 3 and cos(A-B)=4/5, then find its area? Q2)Let the angles of a A,B,C of a triangle ABC be in A.P.and let b:c=under root(3):under root(2).Find the angle A?

Arjun Blouria · Answer

cos(A-B)=4/5 therefore, 1-tan 2 (A-B)/2 = 4/5 1+tan 2 (A-B)/2 By componendo dividendo, 2tan 2 (A-B) = 5-4 2 5+4

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Q1)If in a triangle, a= 6, b= 3 and cos(A-B)=4/5, then find its area? Q2)Let the angles of a A,B,C of a triangle ABC be in A.P.and let b:c=under root(3):under root(2).Find the angle A?

Q1)If in a triangle, a= 6, b= 3 and cos(A-B)=4/5, then find its area?
Q2)Let the angles of a A,B,C of a triangle ABC be in A.P.and let b:c=under root(3):under root(2).Find the angle A?

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Q1)If in a triangle, a= 6, b= 3 and cos(A-B)=4/5, then find its area? Q2)Let the angles of a A,B,C of a triangle ABC be in A.P.and let b:c=under root(3):under root(2).Find the angle A?

Q1)If in a triangle, a= 6, b= 3 and cos(A-B)=4/5, then find its area? Q2)Let the angles of a A,B,C of a triangle ABC be in A.P.and let b:c=under root(3):under root(2).Find the angle A?

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Q1)If in a triangle, a= 6, b= 3 and cos(A-B)=4/5, then find its area?
Q2)Let the angles of a A,B,C of a triangle ABC be in A.P.and let b:c=under root(3):under root(2).Find the angle A?