let 0 prove that sin(x) >= (2x)/pi.

let 0<= x <=90 degees.

  prove that sin(x) >= (2x)/pi.


2 Answers

jitender lakhanpal
62 Points
10 years ago

Dear aritra,

 between 0 to 90 value of 2x/∏ will be 0 to 1 so the and sin is increasing in the interval between 0 to ∏/2 from 0 to 1 

sinx - 2x/∏ is increasing we can check that from differentiation its value also lie between 0 to 1 



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jagdish singh singh
173 Points
10 years ago


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