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Grade: 12 
        
find


tan3A-tan2A-tanA
10 years ago

Answers : (1)

askiitianexpert arulmani
6 Points 
							tan 3A - tan 2A - tan A

tan 3A = tan (A + 2A) = (tan A + tan 2A) / (1 - tan A tan 2A)

tan 3A = (tan A + tan 2A) / (1 - tan A tan 2A)

Bring denominator of Right hand side (2) to the left 

=> tan 3A * (1 - tan A tan 2A) = (tan A + tan 2A)

=> tan 3A - tan A tan 2A tan 3A = tan A + tan 2A 

=> tan 3A - tan 2A - tan A = tan A tan 2A tan 3A

Solution is : tan 3A - tan 2A - tan A = tan A tan 2A tan 3A
10 years ago
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