|sinx+cosx|
a) <=2
b)>=root2
c)<=root2
d<=1/rot2
|sinx+cosx|
a) <=2
b)>=root2
c)<=root2
d<=1/rot2
anurag singhal , 16 Years ago
Grade
Trigonometry> trigo...
1 Answersaskiitian.expert- chandra sekhar
Last Activity: 16 Years ago
Hi Anurag,
|sinx+cosx|=|√2(sin(x+∏/4))|
-1≤(sin(x+∏/4))≤1
-√2≤√2(sin(x+∏/4))≤√2
|√2(sin(x+∏/4))|≤√2
ans: c
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