Grade 12Trigonometry
1 ) If tanA=a/b , then (asinA+bcosA)/(asinA-bcosA)=?
1 ) If tanA=a/b , then (asinA+bcosA)/(asinA-bcosA)=?
2 Answers
sanatan sharma
Approved Tutor Answer14 Years agoif i divide the numerator and denominator by cosA we will get
= ((asinA/cosA)+b)/((asinA/cosA)-bcosA)
= (atanA + b)/(atanA - b)
= (a2 + b2)/(a2 - b2)
Muntasir Mahi
tanA=a/b
=sinA/cosA=a/b
=a/b×sinA/cosA=a/b×a/b
=asinA/bcosA=a2/b2
=asinA+bcosA/asina-bcosA=a2+b2/a2-b2
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