1 ) If tanA=a/b , then (asinA+bcosA)/(asinA-bcosA)=?

Question

sanatan sharma · Answer

if i divide the numerator and denominator by cosA we will get = ((asinA/cosA)+b)/((asinA/cosA)-bcosA) = (atanA + b)/(atanA - b) = (a 2 + b 2 )/(a 2 - b 2 )

Muntasir Mahi · Answer

tanA=a/b =sinA/cosA=a/b =a/b×sinA/cosA=a/b×a/b =asinA/bcosA=a 2 /b 2 =asinA+bcosA/asina-bcosA=a 2 +b 2 /a 2 -b 2

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1 ) If tanA=a/b , then (asinA+bcosA)/(asinA-bcosA)=?

1 ) If tanA=a/b , then (asinA+bcosA)/(asinA-bcosA)=?

2 Answers

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