1 ) If tanA=a/b , then (asinA+bcosA)/(asinA-bcosA)=?
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if i divide the numerator and denominator by cosA we will get
= ((asinA/cosA)+b)/((asinA/cosA)-bcosA)
= (atanA + b)/(atanA - b)
= (a2 + b2)/(a2 - b2)
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