1 ) If tanA=a/b , then (asinA+bcosA)/(asinA-bcosA)=?
1 ) If tanA=a/b , then (asinA+bcosA)/(asinA-bcosA)=?
Nithin Kanagu , 14 Years ago
Grade 12
Trigonometry> Trigonometry...
2 Answerssanatan sharma
if i divide the numerator and denominator by cosA we will get
= ((asinA/cosA)+b)/((asinA/cosA)-bcosA)
= (atanA + b)/(atanA - b)
= (a2 + b2)/(a2 - b2)
Approved Last Activity: 14 Years ago
Muntasir Mahi
tanA=a/b
=sinA/cosA=a/b
=a/bΓsinA/cosA=a/bΓa/b
=asinA/bcosA=a2/b2
=asinA+bcosA/asina-bcosA=a2+b2/a2-b2
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