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1 ) If tanA=a/b , then (asinA+bcosA)/(asinA-bcosA)=?

Nithin Kanagu , 13 Years ago
Grade 12
anser 2 Answers
sanatan sharma

Last Activity: 13 Years ago

if i divide the numerator and denominator by cosA we will get 

= ((asinA/cosA)+b)/((asinA/cosA)-bcosA)

= (atanA + b)/(atanA - b)

= (a2 + b2)/(a- b2)

Muntasir Mahi

Last Activity: 5 Years ago

tanA=a/b
=sinA/cosA=a/b
=a/bΓ—sinA/cosA=a/bΓ—a/b
=asinA/bcosA=a2/b2
=asinA+bcosA/asina-bcosA=a2+b2/a2-b2

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