If sec A+tanA=x , the secA=?

If sec A+tanA=x , the secA=?


1 Answers

Chilukuri Sai Kartik
58 Points
11 years ago

Dear Nitin,

Given that SecA+TanA=x------ Eq.1

We know that Sec2A-Tan2A=1

This is of the form a2-b2=(a+b)(a-b)

So (SecA-TanA)(SecA+TanA)=1

SecA-TanA=1/x   {From eq.1}

Lets consider this as Eq.2


Now adding Eq.1 and Eq.2, we get 2SecA=x+1/x

Hence SecA=(x+1/x)/2


So SecA=(x2+1)/2x


All the best!


Plz approve my answer if you are satisfied.

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