Grade 11Trigonometry
If cos(thita-alpha)=a and cos(thita-beta)=b then the value of [sin^2(alpha - beta)+2abcos(alpha-beta)] will be??
If cos(thita-alpha)=a and cos(thita-beta)=b then the value of [sin^2(alpha - beta)+2abcos(alpha-beta)] will be??
1 Answer
Swapnil Saxena
Approved Tutor Answer14 Years agoAnswer for this quesion is a^2+b^2 . Solution can be found in the attached image.
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