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If cos(thita-alpha)=a and cos(thita-beta)=b then the value of [sin^2(alpha - beta)+2abcos(alpha-beta)] will be??

If cos(thita-alpha)=a and cos(thita-beta)=b then the value of [sin^2(alpha - beta)+2abcos(alpha-beta)] will be??

Grade:11

1 Answers

Swapnil Saxena
102 Points
10 years ago

Answer for this quesion is a^2+b^2 . Solution can be found in the attached image.

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1286_28105_Solution.jpg

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