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If cos(thita-alpha)=a and cos(thita-beta)=b then the value of [sin^2(alpha - beta)+2abcos(alpha-beta)] will be??

Arnab Mandal , 14 Years ago
Grade 11
anser 1 Answers
Swapnil Saxena

Answer for this quesion is a^2+b^2 . Solution can be found in the attached image.

ΓΈ

1286_28105_Solution.jpg

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Last Activity: 14 Years ago
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