Hey there! We receieved your request
Stay Tuned as we are going to contact you within 1 Hour
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-5470-145
+91 7353221155
Use Coupon: CART20 and get 20% off on all online Study Material
Complete Your Registration (Step 2 of 2 )
Sit and relax as our customer representative will contact you within 1 business day
OTP to be sent to Change
if sinx+siny≥cosα.cosx for every x belongs to R,then siny+cosα is equal to ________?
Hi Menka,
This is a good conceptual Question.
Since the inequality is true for every x belonging to R.
It is true even for x = -(pie)/2
So, (-1) + sinY ≥ 0.
So sinY ≥ 1.
But SinY can never be greater than 1. So sinY=1 (always).
And so, SinY+Cos(Alpha) = 1+cos(Alpha) = 2cos2(Alpha/2).
Best Regards,
Ashwin (IIT Madras).
as x belongs to r
let x=0
then
siny>=cosa
y>=90-a
let
y=90-a
then siny+cosa=2siny=2cosa<=2
if y>90-a
siny+cosa<2 for ex:a=0
then y>90 then siny<1 and cosa=1 therefore
siny+cosa<=2
therefore siny+cosa<=2
Get your questions answered by the expert for free
You will get reply from our expert in sometime.
We will notify you when Our expert answers your question. To View your Question
Win Gift vouchers upto Rs 500/-
Register Yourself for a FREE Demo Class by Top IITians & Medical Experts Today !