If A = {x : cosx > - 1/2 and 0 ≤ x ≤ π} , B = {x : sinx > 1/2 and π/3 ≤ x ≤ π}
Then A ∩ B =
(A) [π, 5π/6)
(B) [π, 7π/6)
(C) [π/3, 2π/3)
(D) [0, 5π/6)
The given answer is:
(C) [π/3, 2π/3)
but shouldn't it be [π/6, 2π/3) ?????
Please help......
If A = {x : cosx > - 1/2 and 0 ≤ x ≤ π} , B = {x : sinx > 1/2 and π/3 ≤ x ≤ π}
Then A ∩ B =
(A) [π, 5π/6)
(B) [π, 7π/6)
(C) [π/3, 2π/3)
(D) [0, 5π/6)
The given answer is:
(C) [π/3, 2π/3)but shouldn't it be [π/6, 2π/3) ?????
Please help......
Akshay Kandpal , 14 Years ago
Grade 10
