tanx +tan4x +tan7x=tanxtan4xtan7x
Last Activity: 13 Years ago
Given tanx+tan4x+tan7x=tanxtan4tan7x
We know that tan(a+b+c)=tana+tanb+tanc-tanatanbtanc/1-(tanatanb+tanbtanc+tanctana)
If a+b+c is n(pie),n belongs to N then tan(a+b+c)=0
=> tana+tanb+tanc-tanatanbtanc=0
=>tana+tanb+tanc=tanatanbtanc
it is same as the given question,
Hence , x+4x+7x=n(pie)
=>12x=n(pie)
=> x=n(pie)/12
Last Activity: 11 Years ago
Given tanx+tan4x+tan7x=tanxtan4tan7xWe know that tan(a+b+c)=tana+tanb+tanc-tanatanbtanc/1-(tanatanb+tanbtanc+tanctana) If a+b+c is n(pie),n belongs to N then tan(a+b+c)=0 => tana+tanb+tanc-tanatanbtanc=0 =>tana+tanb+tanc=tanatanbtanc it is same as the given question, Hence , x+4x+7x=n(pie) =>12x=n(pie) =>x=n(pie)/12 Thank YouRuchiAskiitians Faculty
=>x=n(pie)/12
Thank YouRuchiAskiitians Faculty
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