How to find the value of any number lets say 2 such that2^2^2^2^2^....infinity!And also solve:min value of 2^(sinx-1) + 2^(cosx-1) is...???root(2)^[root(2)]root(2)^ [-root(2)]

Dear Abhijat,

Value of such numbers in infinnite and can't be determined,

However we can find th limits of x^x^x^x........ by assuming y=x^x^x^ (1 term less then infinite terms )

Therefore y= x^y

Thus by taking LOG we can evaluate the limting value.

The minimum value of  2^(sinx-1) + 2^(cosx-1) is

root(2)^ [-root(2)]

Best Of luck

Cracking IIT just got more exciting,It’s not just all about getting assistance from IITians, alongside Target Achievement and Rewards play an important role. ASKIITIANS has it all for you, wherein you get assistance only from IITians for your preparation and winexciting gifts by answering queries in the discussion forums. Reward points 5 + 15 for all those who upload their pic and download the ASKIITIANS Toolbar, just a simple click here to download the toolbar….

So start the brain storming…. become a leader with Elite Expert League ASKIITIANS

Thanks

Aman Bansal

Askiitian Expert