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solve these in detail plz : 1)the minimum value of sec²x + cosec²x is ....??? 2)If the max value of cos(cosx) is a and min value is b then b= cos a a =cos b a = 0 b =0 plz explain me how to do questions like this with a good and faster approach..
solve these in detail plz :
1)the minimum value of sec²x + cosec²x is ....???
2)If the max value of cos(cosx) is a and min value is b then
write sec^2 x and cosec^2 x in terms of cos and sine ...
take common denominator
apply cos^2 x + sin^2 x =1;
multiply deno. and numerator by 4
apply sin2x= 2sinx cos x in denominator
u'll get 4/(sin2x)^2
min. value of this term is when deno. is max. which is 1 so ans. is 4,,,,....
plz. approve the ans
Hello abhijat !
Well In case when trignometric function comes in picture...try to reduce in form of a single trignometric function like sinx and cox...because it is known to you that max and minimum value of sin or cos is 1 and -1 ...hence question becomes a bit easier...well i am solving the first one first...
1) sec^2x + cosec^2x
1/sin^2x + 1/cos^2x
taking LCM and solving it .. (sin^2x+cos^2x)/(sinx.cosx)^2
--------------------------------= 1/(sinx.cosx)^2
multiply by 4 up and down ..= 4/(2sinx.cosx)^2
so ....................................= 4/sin^2x
For the minimum value of this expression sin^2x should be maximum ..and hence it comes 4 ...
Question 2 :
Cos(cosx) ---?
Well cosx has maximum value equal to 1 only if x is 0 or 2pi...or multiple of 2pi ...
and the minimum value of cosx is equal to -1 only if x is pi ..or multiple of pi....
Here ...cos(cosx) let it be as ...cos(y) and y as cosx ..
Now ...y will have its value lying between [-1,1] Since zero falls in this range ..hence cos(y) or cos(cosx) has maximum value equal to 1 ...i.e a = 1
But pi doesn't fall in the range of [-1,1] ...so cos(cosx) will never be minimum at pi or it equivalent..it will have a different minimum value ..
Now cosx is a decreasing function ..so if u put x as minimum it will give maximum and if u put it as maximum it will give minimum .. Out concern here is to get minimum value ..
So minimum value of cos(y) is when y(=cosx)=1 ...i.e b = cos1
SO b = cos a
The only way to do such questions in a good and faster approach is practice...solve as much question as u can..u will get confident and feeling that u r approaching fastly and doing good in trignometry ..
Wishes...
Regards
Yagya
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