(secA-cosecA)(1+tanA+cotA)=tanA secA-cotA cosecA
(secA-cosecA)(1+tanA+cotA)=tanA secA-cotA cosecA
krishnan s , 14 Years ago
Grade
Trigonometry> PROVE...
1 AnswersAskiitians_Expert Yagyadutt
Hello Krishna !
It is very simple ...Just multiply each terms in LHS you will get the result ..
(secA - cosecA)(1+tanA+cotA)
= secA + tanA.secA + cotA.secA - cosecA - cosecA.tanA - cosecA.cotA
= secA + sinA.sec^2A + cosecA - cosecA - secA - cosec^2A.cosA
= sinA/cos^2A - cosA/sin^2A
= (sinA/cosA)secA - (cosA/sinA)cosecA
= tanA.secA - cotA.cosecA ( RHS )
Hence proved ...
Regrads
Yagya
Askiitians_expert
Approved Last Activity: 14 Years ago
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