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(secA-cosecA)(1+tanA+cotA)=tanA secA-cotA cosecA

(secA-cosecA)(1+tanA+cotA)=tanA secA-cotA cosecA

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1 Answers

Askiitians_Expert Yagyadutt
askIITians Faculty 74 Points
10 years ago

Hello Krishna !

 

It is very simple ...Just multiply each terms in LHS you will get the result ..

 

(secA - cosecA)(1+tanA+cotA)

 

= secA + tanA.secA + cotA.secA - cosecA - cosecA.tanA - cosecA.cotA

 

= secA + sinA.sec^2A + cosecA - cosecA - secA - cosec^2A.cosA

 

= sinA/cos^2A - cosA/sin^2A

 

= (sinA/cosA)secA - (cosA/sinA)cosecA

= tanA.secA - cotA.cosecA ( RHS )

 

Hence proved ...

 

Regrads

 

Yagya

Askiitians_expert

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