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Dear Ashray,
( 1 - COS X ) / COS X = ( ROOT 2 -1 ) SIN X / ( COS X)
( 1 - COS X) / SIN X = ROOT 2 -1
SQUARING BOTH SIDES
(1-COS X) ^ 2 / [ (1+COS X ) * (1-COS X) ] = 3 - 2 ROOT 2
(1-COSX)/1+COSX = 3 -2ROOT 2
1-COSX = 3 - 2ROOT2 +3COSX -2ROOT2 COS X
2ROOT2 - 2 = COS X * ( 4 - 2 ROOT2 )
COS X = ( ROOT 2 - 1) / ( 2 - ROOT 2)
=1/ROOT 2
>>>> X= PI/4
Best Of luck
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