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2sinA=2-cosA,1-sin^2(A)=4sin^2(A)-8sinA+4,5sin^2(A)-8sinA+3=0,sinA=(8±2)/10,sinA=1 or 3/5
Thanks a tonne sir for the solution, I got an idea but could not understand how did you reach the equation SinA=(8+2)/10 from 5sin^2A-8sinA+3.
wont simple factorization by grouping do? Or it is the latest formulae to obtain the value, if so, kindly illustrate the formulae.
5 sin2A - 8 sinA + 3 { in the form of ax2+bx+c=0 }
which has the roots
Thanx for the answer sir but can you please elaborate the 1st three steps, i will be really gratefull.
Thanx..
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