1. A square tower stands upon a hoizontal plane. From a point in this plane, from which three of its upper corners are visible, their angular elevations are respectively 45, 60 and 45. Show that the height of the tower is to the breadth of one of its sides as [sqrt.6 x (sqrt.5 +1)]/4

Dear shubham,

if we project the problem on horizontal plane we get....

also again by cosine formula

we have cos2@=2cos^2@-1

so....using dis in dese two eqn we have

or

its one of d roots ...other being 1-rt5

 BEST OF LUCK..!!!!

We are all IITians and here to help you in your IIT JEE preparation.

Now you can win exciting gifts by answering the questions on Discussion Forum. So help discuss any query on askiitians forum and become an Elite Expert League askiitian.

Now you score 5+15 POINTS by uploading your Pic and Downloading the Askiitians Toolbar : Click here to download the toolbar.. 

AMAN BANSAL