Q) sin(cot^-1x)+-------

A)1/root(1/x^2) B)root(1/x^2) C)-1/root(1/x^2) D)none

Dear vivek

         cot^-1x = Φ 

so cot Φ = x    

sin  Φ = 1/ √1+x²

 Φ = sin^{-1      1/ √1+x2}

so sin Φ = 1/ √1+x² 

answer is d

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