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If Sin a+ sin2a=1 then,find the value of cos12 a +3cos 10a+3cos 8a+cos 6a-1

neet kavya , 15 Years ago
Grade 11
anser 1 Answers
Pramod J AskiitiansExpert-IIT-B

Dear student,

cos12 a +3cos 10a+3cos 8a+cos 6a-1

can be written as [cos^2 a + cos^4 a]^3 - 1

from given equation sin^2 a  = 1 - sin a => cos^2 a = sin a

=> [ sina a + sin^2 a ]^3 - 1 

=> 1^3 - 1

=> 0

hope it explains !!

Last Activity: 15 Years ago
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