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If Sin a+ sin2a=1 then,find the value of cos12 a +3cos 10a+3cos 8a+cos 6a-1
Dear student,
cos12 a +3cos 10a+3cos 8a+cos 6a-1
can be written as [cos^2 a + cos^4 a]^3 - 1
from given equation sin^2 a = 1 - sin a => cos^2 a = sin a
=> [ sina a + sin^2 a ]^3 - 1
=> 1^3 - 1
=> 0
hope it explains !!
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