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Tan5Θ=(A.tanΘ+B.tan 3 Θ+Tan 5 Θ)/(1+C.tan 2 Θ+D.tan 4 Θ) Then A+B+C+D=? a)0 b)10 c)5 d)15

Tan5Θ=(A.tanΘ+B.tan3Θ+Tan5Θ)/(1+C.tan2Θ+D.tan4Θ)


Then A+B+C+D=?


a)0


b)10


c)5


d)15


 

Grade:12

1 Answers

Saurabh Koranglekar
askIITians Faculty 10341 Points
one year ago
576-562_1.PNG

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