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The value of tan81 - tan63 - tan27 + tan9 is......
(angles are in degrees)
Pls explain.....
tan 81 -tan63 +tan 9 - tan 27=
tan(90-9)-tan(90-27)+tan9-tan27
=cot9-cot27+tan9-tan27
=(sec^2(9)/tan(9))-(sec^2(27)/tan(27))
=(1/(sin(9)cos(9))-((1/(sin(27)cos(27))
=(2/sin(18))-(2/(sin(54))
=4
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