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The number of ordered pair (a,b), where a,b E (-pi,pi),
satisfying cos(a-b) = 1 and cos(a + b) = 1/e ,is.......
(E means 'belongs to')
pls explain.....
cos(a+b)=1/e => a+b=+or-cosinverse(1/e)
cos(a-b)=1=>a=bORa-b=pi the latter does not satisfy cos(a+b)=1/e
hence a=b;
Thus a=b=+OR-cosinverse(1/e)/2
Thus two ordered pairs
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