y=x.sin(x)

I = xsinx dx

choose x as first function & sinx as second & then apply integration by parts ..

I = x(-cosx) - [(-cosx)]dx

I = -xcosx + sinx + C

this is the required result

approve if u like my ans

Dear Jeevan,

Treat x as 1st function & sinx as 2nd function & apply u.v method.

   So I=x(-cosx) - (-sinx)  + c

       I=-x.cosx + sinx + c                 ; c is a constant of integration.

           Hope it works!!!!!!!!

           Plz click Yes below!!!!!!   Thanks!!!!