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y=x.sin(x)
I = xsinx dx
choose x as first function & sinx as second & then apply integration by parts ..
I = x(-cosx) - [(-cosx)]dx
I = -xcosx + sinx + C
this is the required result
approve if u like my ans
Dear Jeevan,
Treat x as 1st function & sinx as 2nd function & apply u.v method.
So I=x(-cosx) - (-sinx) + c
I=-x.cosx + sinx + c ; c is a constant of integration.
Hope it works!!!!!!!!
Plz click Yes below!!!!!! Thanks!!!!
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