Question icon
Trigonometry

If A = 1300 and x = sinA + cosA, then

a) x > 0

b) x < 0

c) x = 0

Profile image of pranshu aggarwal
15 Years agoGrade
Answers icon

1 Answer

Profile image of vikas askiitian expert
ApprovedApproved Tutor Answer15 Years ago

x = sinA +cosA

x/root2 = sinA(1/root2) + cosA(1/root2)

1/root2 = sin45 = cos45

x/root2 = sinAcos45 + cosAsin45

x/root2 = sin(A+45)

if A is 130 then

x/root2 = sin175o > 0                       (sin of angle is +ve in 2nd quadrant)

x > 0

 

option a) is correct