If A = 1300 and x = sinA + cosA, thena) x > 0b) xc) x = 0

x = sinA +cosA

x/root2 = sinA(1/root2) + cosA(1/root2)

1/root2 = sin45 = cos45

x/root2 = sinAcos45 + cosAsin45

x/root2 = sin(A+45)

if A is 130 then

x/root2 = sin175^o > 0                       (sin of angle is +ve in 2nd quadrant)

x > 0

option a) is correct

Approved