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If A = 130 0 and x = sinA + cosA, then a) x > 0 b) x c) x = 0


If A = 1300  and x = sinA + cosA, then


a)      x > 0


b)        x < 0


c)         x = 0


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1 Answers

vikas askiitian expert
509 Points
11 years ago

x = sinA +cosA

x/root2 = sinA(1/root2) + cosA(1/root2)

1/root2 = sin45 = cos45

x/root2 = sinAcos45 + cosAsin45

x/root2 = sin(A+45)

if A is 130 then

x/root2 = sin175o > 0                       (sin of angle is +ve in 2nd quadrant)

x > 0

 

option a) is correct

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