# the smallest +ve root of the equation tanx-x=0 lies in the interval π to 3π/2 prove

Grade:11

## 1 Answers

Arun Kumar IIT Delhi
askIITians Faculty 256 Points
8 years ago
first intersection is at 0,0
then the graph of y=x passes from below y=tan(x)
now at
$tan(3\pi/2-h)$
where h is very small constant
it will tend to infinity
implies y=x will definitely cut it at some point between
$(\pi,3\pi/2)$
because rate of increasing of x is not as much as tan(x)

Arun Kumar
IIT Delhi
Askiitians Faculty

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