Falling Behind in Studies? Join Our Performance Improvement Batch. Enroll For Free
One of our academic counsellors will contact you within 1 working day.
Click to Chat
1800-1023-196
+91-120-4616500
CART 0
Use Coupon: CART20 and get 20% off on all online Study Material
Welcome User
OR
LOGIN
Complete Your Registration (Step 2 of 2 )
Live 1-1 coding classes to unleash the creator in your Child
prove that i. (1 + sin2A - cos2A)/(1 + sin2A + cos2A) = tanA ii. (sinA + sin2A)/(1 + cosA + cos2A) = tanA iii. 2cosA = [2(2 + 2cos4A) 1/2 ] 1/2 iv. 1 + cos56 + cos 58 - cos66 = 4cos28.cos29.sin33
1) (1 + SIN2A - COS2A)/(1+SIN2A + COS2A) = TANA SIN2A =2TANA/1+TAN2A & COS2A =1-TAN2A/1+TAN2A PUTTING THESE LHS =(2TAN2A + 2TANA)/2TANA+2 =TANA = RHS 2) (SINA + SIN2A)/(1+COSA+COS2A) = TANA COS2A = 2COS2A - 1 & SIN2A =2SINACOSA AFTER PUTTING THESE LHS = (SINA+2SINACOSA)/COSA+2COS2A =SINA(1+2COSA) / COSA(1+2COSA) =SINA/COSA=TANA =RHS HENCE PROVED
1) (1 + SIN2A - COS2A)/(1+SIN2A + COS2A) = TANA
SIN2A =2TANA/1+TAN2A & COS2A =1-TAN2A/1+TAN2A
PUTTING THESE
LHS =(2TAN2A + 2TANA)/2TANA+2
=TANA = RHS
2) (SINA + SIN2A)/(1+COSA+COS2A) = TANA
COS2A = 2COS2A - 1 & SIN2A =2SINACOSA
AFTER PUTTING THESE
LHS = (SINA+2SINACOSA)/COSA+2COS2A
=SINA(1+2COSA) / COSA(1+2COSA)
=SINA/COSA=TANA =RHS
HENCE PROVED
Post Question
Dear , Preparing for entrance exams? Register yourself for the free demo class from askiitians.
points won -