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question mark

if A + B =225

prove that

(cotA.cotB)/[(1 + cotA)(1 + cotB)] = 1/2



paradox xyz cool , 15 Years ago
Grade 11
anser 2 Answers
vikas askiitian expert

(COTACOTB)/[(1+COTA)(1+COTB)] = 1/2

TAKING LHS

 

 = (COTACOTB)/[1+COTACOTB +COTA+COTB] ...................1

 

NOW

COT(A+B)=COTACOTB - 1/COTA+COTB

A+B = 225 (GIVEN)

SO

      COT225 = COTACOTB - 1/COTA+COTB

      1 = COTACOTB-1/COTA+COTB                                                  (COT225=1)

  COTA + COTB =COTACOTB - 1 ......................2

PUTTING 2 IN 1 WE GET

   LHS= COTACOTB/2COTACOTB

        =1/2 = RHS

HENCE PROVED

Last Activity: 15 Years ago
sumanth
 

(COTACOTB)/[(1+COTA)(1+COTB)] = 1/2

 

TAKING LHS

 

 

 

 = (COTACOTB)/[1+COTACOTB +COTA+COTB] ...................1

 

 

 

NOW

 

COT(A+B)=COTACOTB - 1/COTA+COTB

 

A+B = 225 (GIVEN)

 

SO

 

      COT225 = COTACOTB - 1/COTA+COTB

 

      1 = COTACOTB-1/COTA+COTB                                                  (COT225=1)

 

  COTA + COTB =COTACOTB - 1 ......................2

 

PUTTING 2 IN 1 WE GET

 

   LHS= COTACOTB/2COTACOTB

 

        =1/2 = RHS

 

HENCE PROVED

Last Activity: 10 Years ago
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