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Grade: 11 
        
prove that:


tan3A.tan2A.tanA = tan3A - tan2A - tanA
8 years ago

Answers : (1)

vikas askiitian expert
509 Points 
							
tan2A can be written as  tan(3A-A)


 


now we have tan(a-b)=tana-tanb/1+tanatanb


here a =2A & b=A


 


tan2A=tan(3A-A)=tan3A-tanA/1+tan3AtanA


 


tan2A(1+tan3Atan2A) = tan3A-tanA


 


 tan2A + tan2Atan3AtanA = tan3A -tanA     or


 


      tan2Atan3AtanA = tan3A -tanA-tan2A


hence proved


 
8 years ago
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