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Grade: 11
        

prove that:


tan3A.tan2A.tanA = tan3A - tan2A - tanA

7 years ago

Answers : (1)

vikas askiitian expert
509 Points
							

tan2A can be written as  tan(3A-A)

 

now we have tan(a-b)=tana-tanb/1+tanatanb

here a =2A & b=A

 

tan2A=tan(3A-A)=tan3A-tanA/1+tan3AtanA

 

tan2A(1+tan3Atan2A) = tan3A-tanA

 

 tan2A + tan2Atan3AtanA = tan3A -tanA     or

 

      tan2Atan3AtanA = tan3A -tanA-tan2A

hence proved

 

7 years ago
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