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prove that
sin^2 24 - sin^2 6= (5^1/2 - 1 )/8
sin224 - sin26 = (51/2-1)/8
we have to prove this
sin2A - sin2B = sin(A-B)sin(A+B)
taking LHS
sin224 - sin26= sin18sin30=(sin18)/2
sin18 = (51/2-1)/4
so LHS becomes
= (51/2-1)/8 =RHS
hence proved
Dear student,
We know that
sin(A + B)sin(A - B) = sin^(2)A - sin^2(2)B
A=24
B=6
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