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min value of
secA + secB + secC is............
Hii Piyush
Look in case of triangle...
cosA + cosB + cosC >= 3/2 ( as A + B + C = 180 )
Now apply AM>GM => (cosA + cosB + cosC)/3 >= ( cosA.cosB.cosC)^1/3
1/2 >= (cosA.cosB.cosC)^1/3 => secA.secB.secC >= 8
Now Again apply AM>GM
(secA + secB + secC)/3 >= (secA.secB.secC)^1/3
so for minimum value of secA + secB + secC ..put secA.secB.secC = minimum i.e = 8
So...secA + secB + secC = 3 X (8)^1/3 = 6 ans
I hope you get it
Regards
Yagya
askiitians_expert
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