Thank you for registering.

One of our academic counsellors will contact you within 1 working day.

Please check your email for login details.
MY CART (5)

Use Coupon: CART20 and get 20% off on all online Study Material

ITEM
DETAILS
MRP
DISCOUNT
FINAL PRICE
Total Price: Rs.

There are no items in this cart.
Continue Shopping

min value of secA + secB + secC is............

min value of


secA + secB + secC is............


 

Grade:12

1 Answers

Askiitians_Expert Yagyadutt
askIITians Faculty 74 Points
10 years ago

Hii Piyush

 

Look  in case of triangle...

 

cosA + cosB + cosC >= 3/2    ( as A + B + C = 180 )

 

Now apply AM>GM   =>   (cosA + cosB + cosC)/3  >=  ( cosA.cosB.cosC)^1/3

 

1/2 >= (cosA.cosB.cosC)^1/3     =>   secA.secB.secC >= 8

 

Now Again apply AM>GM

 

(secA + secB + secC)/3 >= (secA.secB.secC)^1/3

 

so for minimum value of  secA + secB + secC  ..put secA.secB.secC = minimum i.e = 8

 

So...secA + secB + secC =  3 X (8)^1/3 = 6  ans

 

 

I hope you get it

 

Regards

Yagya

askiitians_expert

Think You Can Provide A Better Answer ?

Provide a better Answer & Earn Cool Goodies See our forum point policy

ASK QUESTION

Get your questions answered by the expert for free