• the domain of defination of f(x) =log₂(x+3)/x²+3x+2

f(x)=log₂(x+3)/(x²+3x+2)  =log₂(x+3)/(x+1)(x+2)

x+3>0  =>x>-3   -----(1)

(x+1)(x+2) ≠ 0

x ≠-1,-2  ----(2)

from eq (1) and (2)

domain is (-3,∞)/{-1.-2}