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f(x)=log2(x+3)/(x2+3x+2) =log2(x+3)/(x+1)(x+2)
x+3>0 =>x>-3 -----(1)
(x+1)(x+2) ≠ 0
x ≠-1,-2 ----(2)
from eq (1) and (2)
domain is (-3,∞)/{-1.-2}
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