the domain of defination of f(x) =log2(x+3)/x2+3x+2
rahul verma , 14 Years ago
Grade 12
Trigonometry> finction...
1 AnswersKhushboo Singh
Last Activity: 14 Years ago
f(x)=log2(x+3)/(x2+3x+2) =log2(x+3)/(x+1)(x+2)
x+3>0 =>x>-3 -----(1)
(x+1)(x+2) ≠ 0
x ≠-1,-2 ----(2)
from eq (1) and (2)
domain is (-3,∞)/{-1.-2}
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